(3x-2)(x^2+5x+20)=0

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Solution for (3x-2)(x^2+5x+20)=0 equation: 


Simplifying
(3x + -2)(x2 + 5x + 20) = 0

Reorder the terms:
(-2 + 3x)(x2 + 5x + 20) = 0

Reorder the terms:
(-2 + 3x)(20 + 5x + x2) = 0

Multiply (-2 + 3x) * (20 + 5x + x2)
(-2(20 + 5x + x2) + 3x * (20 + 5x + x2)) = 0
((20 * -2 + 5x * -2 + x2 * -2) + 3x * (20 + 5x + x2)) = 0
((-40 + -10x + -2x2) + 3x * (20 + 5x + x2)) = 0
(-40 + -10x + -2x2 + (20 * 3x + 5x * 3x + x2 * 3x)) = 0
(-40 + -10x + -2x2 + (60x + 15x2 + 3x3)) = 0

Reorder the terms:
(-40 + -10x + 60x + -2x2 + 15x2 + 3x3) = 0

Combine like terms: -10x + 60x = 50x
(-40 + 50x + -2x2 + 15x2 + 3x3) = 0

Combine like terms: -2x2 + 15x2 = 13x2
(-40 + 50x + 13x2 + 3x3) = 0

Solving
-40 + 50x + 13x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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